Elimination (E2) of alkyl halides to give alkenes

by James

Description: Addition of strong base to an alkyl halide results in elimination to form a new C–C π bond.
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{ 3 comments… read them below or add one }


Very helpful thank you!


proud indian

the reaction is 100 percent anti and the halide ion and the hudrogen atom that is polarised by the strong base shouid be diametrically opposite and the molecules periplaner . it seems to be a reaction of two steps bt is single step reaction


James Briscoe

Question: if isobutyl bromide is treated with -OH and H2O would this result in an E2 and SN2 reaction? I’m assuming that even though H2O is a polar protic solvent and -OH is a strong nucleophile the H2O would not affect -OH since it is -OH’s conj. acid. I’m thinking in this case with no heat added you would observe a competition between the -OH anion either deprotonating the single H from the beta carbon acting as a Lewis Base or a substitution resulting in an attack at the alpha carbon and replacement of Br with -OH? I guess seeing both -OH and H2O threw me off.


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