Hydrolysis of acetals to give aldehydes and ketones
Description: Addition of aqueous acid to acetals will transform them back into ketones (or aldehydes). This is often referred to as “deprotection” of ketones (or aldehydes).
- Acid may be written simply as “H+” . Many different acids will suffice here.
- The reaction is an equilibrium. Water is generally used as the solvent here. Since it is present in vastly greater excess relative to alcohol, the reverse reaction is negligible.
- Acid is catalytic
- The reaction can be used to “protect” the carbonyl against attack, since acetals are not reactive.
Notes: Example 3 is an example where both alcohols come from the same molecule, this makes a cyclic acetal
Mechanism: The reaction begins by protonation of one of the oxygens of the acetal (Step 1, arrows A and B), which makes a better leaving group, 1,2-elimination of the alcohol (Step 2, arrows C and D) leads to an oxonium ion, which is then attacked by water in a 1,2-addition (Step 3, arrows E and F). Proton transfer from water to alcohol (Step 4, arrows G and H) again makes the alcohol a better leaving group, which is displaced through 1,2-elimination (Step 5, arrows I and J) forming a protonated ketone. This is then deprotonated (Step 6, arrows K and L) to give the neutral ketone.
- There are other reasonable mechanisms for proton transfer in step 3.
- Furthermore there are several other species that could act as bases in step 6. TsO(–) is chosen for simplicity.
- Although each step is reversible, single arrows are shown here for simplicity.