Calculating the oxidation state of a carbon

by James

in General Chemistry

By the end of gen chem, calculating oxidation states of different metals should be pretty familiar. Here’s what you do. Take a typical compound – FeCl3, for instance.  Treat every bond between the metal and a different atom as if it were an ionic bond. That means the more electronegative elements (like chlorine, say, or oxygen) bear negative charges, and the less electronegative element (such as the metal) bears the positive charge.

If the compound is neutral, the sum of the oxidation states also has to be neutral. (If the compound has a charge, you adjust the oxidation states accordingly so that their sum equals the charge).

Now here’s a fun exercise. Try applying the same rules to carbon.

It’s going to feel a little bit weird. Why? Because there are two key differences.

  • First, carbon is often more electronegative (2.5) than some of the atoms it’s bound to (such as H, 2.2). So what do you do in this case?
  •  Secondly, unlike metal-metal bonds, carbon-carbon bonds are ubiquitous. So how do you deal with them?

Two answers.

  1. In a C-H bond, the H is treated as if it has an oxidation state of +1. This means that every C-H bond will decrease the oxidation state of carbon by 1.
  2. Any two bonds between the same atom do not affect the oxidation state (recall that the oxidation state of Cl in Cl-Cl (and that of H in H-H) is zero. So a carbon attached to 4 carbons has an oxidation state of zero.

So unlike metals, which are almost always in a positive oxidation state, the oxidation state of carbon can vary widely, from -4 (in CH4) to +4 (such as in CO2). Here are some examples.


(Don’t forget that this is called a “formalism” for a reason. The charge on the carbon isn’t really +4 or –4. But the oxidation state formalism helps us keep track of where the electrons are going, which will come in handy very soon).

With an understanding of how to calculate oxidation states on carbon, we’re ready for the next step: understanding changes in the oxidation state at carbon, through reactions known as oxidations (where the oxidation state is increased), and reductions (where the oxidation state is reduced). More on that next time.

Related Posts:

{ 10 comments… read them below or add one }

azmanam July 25, 2011 at 11:26 am

I made a big chart of this one day.

I’ll have more to say on this, but I’ll wait til the next post where I suspect it will be more in context :)


James July 25, 2011 at 12:00 pm

Beautiful!!!! Are you going to make a large version available?


azmanam July 25, 2011 at 12:41 pm

What do you mean by “large version”? The png is 1175px x 2120px. It’s just over 2 landscape chemdraw pages tall. You should be able to zoom in on the picture to get a larger version.

I redid it slightly just now to make it more general and less specific (now listing the oxidation state of any methylene carbon, not just the oxidation state of propane). The new version’s on the chem reddit and here:


James July 25, 2011 at 1:35 pm

My error. Looks amazing. Looking forward to the post!


PostBacc July 27, 2011 at 8:01 am

This is very helpful. You should compile all your posts into an e-textbook or something similar. Subscribed.


MJ February 19, 2013 at 7:18 am

“With an understanding of how to calculate oxidation states on carbon, we’re ready for the next step: understanding changes in the oxidation state at carbon, through reactions known as oxidations”

Were you planning on making a post specifically on this topic?


LAL BAHADAR June 14, 2013 at 2:05 am

why an atom shows different oxidation states.


james June 19, 2013 at 9:02 pm

That is a very deep question and not so simple to answer.


Prakash July 11, 2013 at 4:43 am

Because dat is having different electronegative atoms


Sonia November 2, 2014 at 1:25 am

Yaay! I love this!! Helped me so much in understanding biochemical reactions :)

Thanks James.. wish I could like this on facebook or something :)


Leave a Comment