By James Ashenhurst

5 Key Basicity Trends of Amines

Last updated: January 17th, 2023 |

5 Key Amine Basicity Trends

What are the most important factors that affect the basicity of amines? Here are 5 key trends.

  • Basicity increases with increasing negative charge on nitrogen. (e.g. NH2 > NH3 ).
  • Conjugated amines are less basic than comparable non-conjugated amines, since the lone pair is delocalized into the pi-bond.
  • Inductive effects (nearby electron-withdrawing groups) reduce the basicity of amines.
  • The basicity of NH2 will be decreased if it is next to a ‘pi-acceptor‘ such as C=O to which it can donate a pair of electrons. Amides are less basic than amines.
  • The basicity of nitrogen is highest for sp3-hybridized nitrogen (e.g. CH3NH2) and is lowest for sp-hybridized nitrogen (e.,g. CH3CN).

summary of factors that affect amine basicity conjugation charge hybridization

Table Of Contents

  1. Basicity Is A Reflection of Electron-Pair Instability
  2. Basicity Trend #1: Basicity Increases With Increasing Negative Charge On Nitrogen
  3. Basicity Trend #2: “Resonance”, or, Conjugated versus Non-Conjugated Amines
  4. Basicity Trend #3: Inductive Effects Decrease Basicity
  5. Basicity Trend #4: Pi Acceptors and Pi Donors
  6. Nitrogen Is Less Basic When It Is A Pi-Donor
  7. Nitrogen As A Pi-Acceptor
  8. Basicity Trend #5: Hybridization
  9. Bonus Factor: Aromaticity
  10. Conclusion: Amine Basicity Trends
  11. Notes

1. Basicity Basics

Previously, we’ve seen how to evaluate the basicity of amines by examining the pKa of its conjugate acid (pKaH). (The higher the pKaH, the stronger the base).  But we haven’t yet dug into the key concepts that help us evaluate, for example, why pyridine (pKaH = 5.2) is less basic than piperidine (pKaH = 11), or why the nitrogen of a nitrile is much less basic than the nitrogen of an amine. That’s our topic for today.

Thankfully, even if you’re just getting started on amines, this subject shouldn’t really be that new to you. You’ve likely encountered the problem of evaluating how acidic certain molecules are – such as, for example, in the 5 key factors that affect acidity.

From that unit, you may recall that  any factor which makes a molecule’s conjugate base more stable will increase its acidity.   [Remember Le Châtelier? If you make the product more stable, you’ll favor the equilibrium going to the right].

What each of the “factors that increase acidity” have in common is that they tend to stabilize negative charge, either through inductive effects, delocalization through resonance, or by bringing the charge closer to the nucleus.

Since acidity and basicity are opposite sides of the same coin, the key factors which affect acidity also affect the basicity of amines. [Note 1] So evaluating basicity involves taking those same concepts but working in the opposite direction.

Generally speaking, the more unstable an electron pair is, the more basic it is. So using the same principles we outlined above, one could increase basicity by removing inductive effects, removing delocalization through resonance, or bringing the charge farther away from the nucleus.

Let’s examine the key factors in turn and apply them to obtain some key trends for the basicity of amines.

2. Basicity Trend #1: Basicity Increases With Increasing Negative Charge On Nitrogen

This is possibly the simplest factor to evaluate. If “basicity” can roughly be translated as “electron-pair instability”, and instability increases with charge density, then basicity should increase with increased negative charge.

A simpler way to put it: the conjugate base of an amine will always be a stronger base than the amine itself.

Compare ammonia, (NH3) with its conjugate base, the amide anion NH2(-). The amide anion is stronger base by far (pKaH of 38, versus pKaH of 9). It can be used to deprotonate terminal alkynes (pKa = 25), for example, whereas ammonia will not.


Continuing this trend, the conjugate base of the amide ion, the amide dianion NH(2-) should be an even stronger base, but it seems to be prohibitively difficult to make.

3. Basicity Trend #2: “Resonance”, or, Conjugated vs. Non-Conjugated Amines 

This relationship between lower charge densities giving rise to lower basicity also applies to lone pairs that can be delocalized into a larger pi system through resonance.

You may recall that  phenol (pKa = 10) is a much stronger stronger acid than cyclohexanol (pKa = 16).

Since, “the stronger the acid, the weaker the conjugate base”, this is equivalent to saying that the conjugate base of phenol is a weaker base than the conjugate base of cyclohexanol.

Why? We saw earlier that this is true because the conjugate base of phenol can be stabilized through resonance whereas the conjugate base of cyclohexanol cannot.

 The oxygen in phenol is part of a larger “pi system”, and the electron density can be distributed throughout the aromatic ring via resonance. (Remember: lower charge density = more stability).

phenol is a stronger acid than cyclohexanol because conjugate base is stabilized through resonance

Let’s apply this to amines.

By analogy, we should also expect that aminobenzene (“aniline”) is a weaker base than cyclohexylamine.

That is indeed the case! The the pKaH of aniline is 4.6, and pKaH of  cyclohexylamine is 11.2. (The higher the pKaH, the stronger the base).

The basicity is decreased even further when a second phenyl ring is attached to the nitrogen (pKaH = 0.78).

amines stabilized through resonance are weaker bases

The bottom line here is that all else being equal, a conjugated amine will be less basic than a non-conjugated amine.

4. Basicity Trend #3. Inductive Effects Decrease Basicity

You may recall that electron withdrawing atoms (e.g. F or Cl) or functional groups (e.g. NO2) tend to increase acidity, by slurping away electron density from the conjugate base. Trifluoroethanol (pKa = 12.5)  for example, is far more acidic than ethanol itself (pKa = 16).  Lower charge density = more stability = lower basicity. 

Hence, we’d expect that electron withdrawing groups on amines should likewise decrease their basicity. And they do! Witness morpholine (pKaH = 8.36) compared to piperidine (pKaH = 11), or 2-chloropyridine (pKaH = 0.49) versus pyridine (pKaH = 5.2).

electron withdrawing groups on amines decrease basicity eg morpholine and 2 chloropyridine

5. Basicity Trend #4: Pi-Acceptors and Pi-Donors

We’ve seen that resonance tends to decrease basicity (Factor 2) and so do inductive effects (Factor 3).

That said, how do you explain why amides are significantly less basic than amines? Is it resonance? Is it inductive effects? Is it both?

why is basicity of amides much lower than that of amines

It seems worthwhile to devote a section to how the basicity of nitrogen is affected by its interactions with other functional groups in a pi-system.

Specifically, the basicity of nitrogen is decreased when it acts as a pi-donor, and the basicity of nitrogen is increased when it acts as a pi-acceptor.

6. Nitrogen Is Less Basic When It Is A Pi-Donor

Back to our amide example. Why is it less basic?

The first factor is that an electron-withdrawing oxygen is present, which can remove some of the electron density from nitrogen. However, this is outweighed by the fact that there is a significant resonance form where the nitrogen lone pair forms a new pi bond with carbon (we call this, “pi-donation“) resulting in a pair of electrons moving from the C-O pi bond to the oxygen (we call this acting as a “pi acceptor“).

nitrogen is strong pi donor and basicity is decreased adjacent to a carbonyl due to pi bond formation

Look at that resonance form on the right. The nitrogen doesn’t have a lone pair anymore, and therefore it cannot act as a base. 

Therefore, the basicity of a nitrogen is decreased when attached to a pi-acceptor. 

What are pi-acceptors, again? If you’ve covered electrophilic aromatic substitution, these functional groups should seem familiar.  You might recognize that “Pi acceptors” all belong in the category of  “meta- directors” .

examples of pi acceptors in resonance ketone nitro sulfonyl nitrile

[CF3 is an example of a functional group that is a meta director but not a pi acceptor, since it has no pi bonds]

7. Nitrogen As A Pi-Acceptor

You might rightly ask if this can work in the opposite direction.

Can the basicity of a nitrogen be increased when it is attached to a pi-donor? Absolutely.

A great comparison is pyridine (pKaH = 5.2) and 4-dimethylamino pyridine (DMAP). Attachment of the strongly pi-d0nating NMe2 group to the 4-position results in a 104 increase in basicity of the ring nitrogen (pKaH = 9.2). Examining the resonance forms of DMAP is illuminating. In the key resonance form, the nitrogen in the ring bears a negative charge.

pi donation increases basicity of nitrogen example dmap is more basic due to pi donation

The ring nitrogen of DMAP is the most basic nitrogen, not the NMe2! The NMe2 is made less basic by being a pi-donor (see above) but the pyridine nitrogen is made more basic because it is the pi-acceptor here.

Another example of how basicity of nitrogen can be increased by attachment to pi-donors is found in guanidines.  In guanidine there are two pi-donating NH2 groups which can donate electron density to the (pi-accepting) C=NH.


Those of you who have studied some biochemistry might recall that arginine is the most basic of all the 20 essential amino acids (pKaH = 12.5).

8. Basicity Trend#5 : Hybridization 

One of the more remarkable acidity trends is that alkynes are unusually acidic (pKa = 25) relative to alkenes (pKa‘s around 43) and alkanes (pKa‘s >50).

effect of hybridization on acidity alkynes stronger acids than alkanes

You might recall that our explanation for this effect was that the sp-hybridized orbitals of alkynes bear 50% s-character, and as the 2s orbital is closer to the nucleus than the 2p orbitals, the resulting lone pair of the conjugate base “feels” more of the positive charge from the nucleus than would a lone pair in an sp3 hybridized orbital (25% s-character). It’s similar to why a lone pair is more stable on a more electronegative atom like fluorine than on a less electronegative atom like carbon.

Knowing this, how would you predict the relative basicity of nitriles, pyridine, and piperidine?

-basicity of nitrogen increases as p character increases so sp3 more basic than sp2 more basic than sp

By analogy to alkynes, we’d expect the lone pairs in sp-hybridized nitriles to be the most stable and hence the least basic. We’d therefore expect the lone pairs in sp3-hybridized amines to be the least stable and hence the most basic.

This is borne out by pKaH values. The pKaH of benzonitrile (pKaH = –10) indicates that nitriles are very weak bases indeed. We can likewise explain the lower basicity of pyridine (pKaH = 5.2) versus piperidine (pKaH = 11) by the orbital hybridization.

(Not resonance, by the way! The lone pair in pyridine is in the plane of the ring, and thus not in conjugation with the p-orbitals). 

9. Bonus Factor: Aromaticity

Classic exam question. What’s more basic, pyridine or pyrrole?

quiz - what is stronger base pyridine or pyrrole

It turns out that the nitrogen in pyrrole is unusually non-basic. In fact, even when subjected to acid, pyrrole reacts at carbon (C-2), and not on the nitrogen. Pyridine [pKaH = 5.2] is far more basic than pyrrole [pKaH about –3.6 ]


Draw the conjugate acid of pyrrole. Notice anything?

to understand basicity strength examine acidity of conjugate acid pyrrole is poor base

The conjugate acid is not aromatic.  Removal of the lone pair on nitrogen through protonation would destroy the conjugation of the lone pair with the other p orbitals of the ring and render the molecule non aromatic.

This might ring a distant bell. You might remember that cyclopentadiene is an unusually strong acid for a hydrocarbon. We can restate this as “the conjugate base of cyclopentadiene is unusually weak”.

cyclopentadiene is very strong acid for a hydrocarbon due to aromatic conjugate base

See the analogy with pyrrole? Protonation of the cyclopentadienyl anion destroys aromaticity.

The bottom line here is to be on the lookout for situations where forming a new N-H bond might disrupt aromaticity. [Note 2]

Can you apply the same concept in the question below?

quiz what would be most basic nitrogen in each molecule imidazole 7-azaindole

10. Summary: Amine Basicity Trends

OK, I said there were 5 factors which affected acidity, but I covered six factors here. The reason is that “pi donation” and “pi accepting” behaviour often doesn’t get covered that much in Org 1 (when acidity is introduced) but by the time most students encounter amines, they’ve encountered these concepts in the context of electrophilic aromatic substitution.

The key lesson for today is this: since “the stronger the acid, the weaker the conjugate base” and “the weaker the acid, the stronger the conjugate base”, every factor that affects acidity is likewise a factor that affects basicity.

If you understand the factors that stabilize negative charge (and therefore make an atom less basic), by definition you also understand the factors that destabilize negative charge (and therefore make an atom more basic).

How do we handle situations where multiple factors come into play? We must resort to experimental measurement (pKaH). It’s too difficult to predict trends when more than one variable is being changed at once.

In the next post we’ll look at a very specific example of this – and, I may add, a common exam problem. : – )

Thanks to Prof. Paul Wenthold (Purdue U) for a very helpful email. 


Note 1.  Because we’re only discussing the basicity of nitrogen here, the atomic factors of electronegativity and polarizability aren’t discussed.

Recall, however, that across a row of the periodic table, basicity is inversely correlated with electronegativity. H3C(-) is more basic than H2N(-) which is more basic than HO(-) which is more basic than F(-). The less electronegative the element, the less stable the lone pair will be and therefore the higher will be its basicity.

Another useful trend is that basicity decreases as you go down a column of the periodic table. This is because the valence orbitals increase in size as one descends a column of the periodic table. The electrons will therefore be “spread out” over a larger volume, resulting in lower charge density . Our common way of describing this is by using the term “polarizability”.

Note 2. Here’s a fun example where nitrogen is unusually basic due to aromaticity. A family of imine “superbases” has been developed by the research group of Tristan Lambert at Columbia (update: now Cornell)

tristan lambert strong basicity of cyclopropene imines

Note how a significant resonance form of the conjugate acid is a substituted version of the aromatic cyclopropenium cation. This helps to drive the equilibrium towards the conjugate acid. The pKaH here is about 27!

See: Jeffrey S Bandar and Tristan H Lambert, Journal of the American Chemical Society, 134(12), 5552-5555 (2012)

(Advanced) References and Further Reading

  1. Basicity of N-substituted anilines and pyridine in dimethylsulfoxide
    Robert L. Benoit, Moyra J. Mackinnon, and Leon Bergeron
    Can J. Chem. 59, 1501 1981
    “[For amines] in the gas phase the basicity order is Me3N > Me2NH > n-PrNH2 > MeNH2 > NH3  while in the solvent dimethylsulfoxide (Me2SO) the order becomes MeNH2 ~ EtNH2nPrNH2 > NH3 ~ Me2NH >> Me3N. Thus NH3 is more basic than Me3N by 2.0 pK units. Then in water, the sequence changes to Me2NH ~ EtNH2 ~ MeNH2n-PrNH2 > Me3N > NH3 so that NH3 is now a weaker base than Me3N with a 0.6 pK difference. “


Comment section

25 thoughts on “5 Key Basicity Trends of Amines

  1. sir, why is basicity NH3 < aniline in gas phase? Nitrogen of NH3 is sp3 and aniline is sp2.
    And, why is basicity aniline < NH3 in water?

  2. Hi James,
    In the summary card/diagram, you say that basicity increases with increasing s character. But it should say “decreasing” s-character like you did below.

  3. sir. i am working on oleylamine ligand but it is hard acidity. i like to convert into softer amine ligand bu screening its tail. whats your suggestion to got softer oleylammonium ion for interaction with soft iodide in CsPbI3 QDs structure

  4. The subpoint no.2, in point 3 – How’s aniline more basic (i.e. less acidic) than the other compound (with 2 benzene rings) ? Doesnt the lone pair get distributed on both rings as opposed to one? And if that happens then neither of the rings will have good resonance. But with Aniline that’s not the case. Kindly clarify my confusion. Thank you :).

    1. The key point is that in diphenylamine the lone pair on nitrogen can be delocalized through two aromatic rings. Maybe I’m not fully grasping your question, but this doesn’t appear to have any significant impact on the resonance (or aromaticity) of the aromatic rings, given the low value obtained for the pKa of protonated diphenylamine.

  5. Thank you very much for the quick reply, I am really interested in the nucleophilic capacity of these compounds, I have read that basicity and nucleophilic capacity are related, in this case does the chain length affect the nucleophilic capacity or is it still negligible?

  6. Dear Dr James
    I am working with propylamine and octylamine, Tthe difference between them is the carbonate chain, but which one is more basic

  7. Dear Dr James!

    Just to appreciate you for your effort which is a great help for both students and instructor both. Keep it up. Master Organic Chemistry is In-depth concept source with incredibly simplest yet technical way.

  8. Thanks a lot. Literally i have not seen anywhere throughout the internet where organic chemistry is taught in such a beautiful manner.Hats off to you. You have amazing teaching skills.Please feel proud of yourself.

  9. Sir, can u tell me why o-methyl aniline is less basic than aniline despite electron donating tendencies of -CH3 group? It seems Steric Inhibition of Resonance is the answer. But how?

    1. In order for the oxygen to be able to donate its pair of electrons into the ring, it has to adopt sp2 hybridization (trigonal planar geometry). This puts the methyl group attached to the oxygen in the same plane as the aromatic ring. If you draw it out, you should see the problem!

  10. sir please give some information about pyramidal inversion( not only amine inversion).
    i’m really confused .also discuss the cases in which inversion will occur. Also is inversion there in cyclic compounds containing nitrogrn phosphorous etc. and plz do it early , my exam is close.

    1. Pyrimidal inversion: important for nitrogen, but doesn’t happen (at low temperatures anyway) for phosphorus. Look at a chiral phosphine like DIPAMP for instance. You can resolve it.
      Inversion of amines passes through an sp2 hybridized intermediate, so when sp2 hybridization is disfavored due to strain it is less likely. Aziridines, for example, as well as in bases like quinuclidine and dabco.

    1. In inversion of amines an sp3 hybridized nitrogen passes through a planar sp2 intermediate en route to the inverted sp3 nitrogen. In theory one would expect that an sp3 hybridized nitrogen would be more basic than an sp2 hybridized nitrogen than an sp hybridized nitrogen. Amines are more basic than nitriles after all. Therefore one could look at nitrogens in systems where inversion is impossible and compare their basicities to nitrogens where inversion happens. One good comparison would be, say, triethylamine with quinuclidine. The pkaH of triethylamine is 10.75 versus 11.0 for quinuclidine, indicating that this could indeed have a minor effect. Great question. See the Evans pka table:

    2. Great question Mudasir. Basicity decreases with amine s-character, so sp3 nitrogen is more basic than sp2 which is more basic than sp. Inversion of amines involves passing through an sp2 hybridized intermediate. Drawing an an analogy with resonance, you can think of this as a contribution of “sp2 character” to the overall basicity of the amine. When you have a base like quinuclidine or DABCO that can’t invert there is a lower population of sp2 hybridized nitrogen, therefore one would expect higher basicity. That’s my stab at it. James

  11. Thank you for granting access to the informative and educational technical paper. My question is: if I want to reverse the Lyotropic selectivity of sulfate first and chloride second in a Type 1 strong base anion exchange resin (tertiary amine or quaternary amine) to chloride first and sulfate second, what high basicity amines are best suited in the amination step post chloromethylation? Thank you.

Leave a Reply

Your email address will not be published. Required fields are marked *

This site uses Akismet to reduce spam. Learn how your comment data is processed.