Any time a new bond is formed, take a look at the atom that’s accepting the lone pair of electrons. Does it have a full shell of electrons? Oftentimes it does. If so, that means you’re going to have to break a bond that’s attached to that atom. If it’s a single bond you’re breaking, what you end up creating is called a leaving group.
Note how the second arrow always shows a pair of electrons going toward the leaving group. That means the charge on it is going to become more negative by 1 when it leaves. So if the leaving group is positively charged, it will become neutral, and if it’s neutral, it will become negative.
The identity of the leaving group is crucial to whether the reaction will happen at all. There are “good” leaving groups and there are “bad” leaving groups. Reactions are more likely to take place when you can displace a good leaving group.
What makes a leaving group “good” or “bad”? Thankfully, there’s one simplifying factor to look at when deciding this: its basicity. Good leaving groups are weak bases.
How do we know what are weak bases? There’s a useful tool for that – it’s called a pKa table. Many pKa tables only specifically give you the identity of the acid, but if you think about it, it also gives you information about the conjugate base of each acid. The conjugate base is the part left over when you lose H+. The stronger the acid, the weaker the conjugate base.
And the weaker the conjugate base, the better the leaving group. So a pKa table is a great guide to leaving group ability.
One word of caution: pKa measures an equilibrium, whereas leaving group ability is based on reaction rates. So although the correlation is very good, it isn’t perfect.
Here’s a pKa table, annotated.
The trend is pretty clear – in general, the weaker the base, the better the leaving group. Furthermore, note how we (almost) never see alkanes or hydrogens as leaving groups. That’s because they’re strongly basic anions – and very unstable.
You might note that I have carefully avoided discussing fluorine. Fluorine tends to be a very poor leaving group for SN1/SN2/E1/E2 reactions. In Org 2, you may see some examples where F can act as a leaving group when it is attached to a carbonyl carbon or an aromatic ring. These reactions (addition-elimination reactions) are a little bit different in that the rate determining step is not so related to loss of the leaving group. There are some extra factors at work in these situations that we can discuss if you’re curious.
Next Post: Leaving Groups Are Nucleophiles Acting In Reverse
The Hofmann and Curtius Rearrangements
Reducing Sugars
Cyclic Dienes and Dienophiles in the Diels-Alder Reaction
Reductive Amination
The Diels-Alder Reaction
3 Trends That Affect Boiling Points
What Makes A Good Nucleophile?
Five Key Factors That Influence Acidity
Polar Protic? Polar Aprotic? Nonpolar? All About Solvents
Table of Functional Group Priorities for Nomenclature
{ 56 comments… read them below or add one }
This is gold !!.. Thanks alot
Thanks!
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Which is the good living group phenoxy ( PhO) or chloride (Cl)?
What’s a weaker base?
Which is the good leaving group phenoxy (PhO) or Chloride Cl?
Procedure for you figuring this out for yourself: Go to a pKa table and figure out the pKa of Phenol (PhOH) and HCl. Which is a stronger acid? Now: the stronger the acid, the weaker the conjugate base. . So which of these would have the weaker conjugate base? The weaker the base, the better the leaving group.
phenol has a pKa of about 16 and HCl has a pKa of about -5 so “strong acid weak conjugate base” would imply that Cl- is the better leaving group.
anyone knows HCl is a strong acid!! STUPID
hcl is a strong acid and it is the better leaving group
how did you get through general chemistry not knowing that?!
phenol at about 10 pka, HCl at about -7 pka. So HCl is the stronger acid=weaker conj. base = more stable as an anion = better leaving group. Do I have this thought process correct?
The most understandable way I have ever seen! Thank you very much, please keep up the good work.
Glad you find it helpful Ivana! thanks
Thank you so much. Very lucid and informative. Please keep it up.
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Glad you’re finding it useful. When you’re done, tell your friends :-)
Yes, please discuss the extra factors you mentioned regarding F- in a-e rxns.
Thanks so much for always making it clear and interesting!
What happens if the leaving group is positive, making the charge on the carbon neutral, like S+(CH3)2?
Ah… well the leaving group would be S(CH3)2 which is a very weak base and an excellent leaving group ! (much like OH2(+)]
This is just what I need,Organic chemistry has been a part of chemistry that seemed to be impossible to understand. But with the help of your explanations I see my self getting a straight A,beyond the shadow of doubt. Thanks to you James.
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There is a mistake in the second paragraph, I think. An atom can never be neutral and charged at the same time. A neutral atom’s atomic number(number of protons) is the same as the number of electrons. I recommend you to say an atom becomes an ion(negatively charged) to reach the full octect.
keep up your good work. your site really helped me and my friends most of the concepts in organic chemistry.
That’s so helpful! You made very simple. Are there other factors beside PKa? what about the bond strength effect in case of a hydroxy gp attched to a carbon…
Thank James
Is CN- a good leaving group
No, it’s quite a poor leaving group
Thanks! But can u explain plz why weak bases are better leaving groups?
Where would O-Ph rank as a leaving group? Is it better than the halides?
the site is excellent, thank you very much, you had solved most of my problems in organic chemistry.
By far the most coherent explanation of nucleophiles and leaving groups I have seen so far. Better than Youtube and most text books for that matter!
What if there are two identical leaving groups on different parts of the molecule? Say, two bromines. What factors do you look at when choosing the leaving group then?
Then you would examine the carbon that the leaving groups are attached to. Primary, secondary, or tertiary? Then you would look at the reaction conditions (i.e. what nucleophile is present?). This then leads into the SN1/SN2/E1/E2 decision. You might want to check my “Quick N’ Dirty Guide to SN1/SN2/E1/E2 for more information there because it’s a lot to summarize in a blog comment.
I ve seen alkoxides getting removed during sn2th reactions (related to carbonyls) . I’m in a mess and get choked up in such reactions.please help
Thank you so much!
Minor fix needed on the first image: the reactants side is neutral while the products side is positive (need to either add a negative formal charge to Nu or take off the negative formal charge from L).
Could u explain why F can become a leaving group when it is attached to a carbonyl carbon or an aromatic ring?
Yes, F- is an OK leaving group in those situations (nucleophilic aromatic substitution) because the rate limiting step is attack of the aromatic ring (disrupting aromaticity). Loss of the leaving group is slow compared to that step. Also, because F- is so electron withdrawing, F actually helps to accelerate the reaction by removing electron density from the ring and making it easier to attack.
this is a great website which is helping for my exams very much clarifies my doubts in organic chemistry can you tell me why flurine is a exeption and in a carbonyl carbon or an aromatic ring acts as a good leaving group compared to other halogens
I- is a BLG than F- in aprotic solvents.
F- is a BLG than I- in protic solvents .
If something is a poor nucleophile it has to be BLG.
I am right , right ?
asking this because I read poor bases are BLG which I accept ,but I think that it should differ in solvents.
(Ex:F- in protic is much more stable than I- due h bond.)
someone please tell me if I am right or not.
F-
why iodine is a good leaving group as well as a good nucleophile
Thank you so much!
These articles really help. Continue the good work. Cheers from India !
+NR3 is the best leaving group.
Could you please explain the fluoride ion exception?
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Awesome website, explains the any topic with ease. Whenever I have any doubt I refer MOC, it helps me a lot. Thank you Mr. James for your remarkable efforts. You have made learning organic chemistry interesting through this website.